So I have filtered the copper and washed with water several times - prettymuch 100% recovery. As expected, as it won't dissolve with H₂SO₄ unless H₂O₂ is present.
Next step was to begin to precipitate the aluminium from the clear solution of Al³⁺ ions in dilute H₂SO₄ using 10 M NaOH. Every 100 ml was 1 mole of NaOH.
Stoichiometrically speaking, 1 mole of H₂SO₄ was already used up to react with the aluminium, and there was an additional 1 mole of H₂SO₄ as an excess. So 2 moles of NaOH are needed to neutralise the excess mole of sulfuric acid, and an additional 1 mole of NaOH is needed to turn all Al₂(SO4)₃ into Al(OH)₃.
pH still below 6 here:

- Al Cu H2SO4 experiment 3.jpg (181.85 KiB) Viewed 406 times
Then, after adding 3 moles of NaOH (300 ml of 10 M solution) all the Al(OH)₃ precipitated as a giant gluggy mess!

- Al Cu H2SO4 experiment 4.jpg (150.49 KiB) Viewed 406 times
So my real question was to see if I could take the pH well past neutral and get all of the aluminium to go back into solution. Again, stoichiometrically speaking, an additional 1 mole of NaOH is required to react with the newly formed Al(OH₃) gloop, to form NaAlO₂. So after adding a total of 5 moles of NaOH:

- Al Cu H2SO4 experiment 5.jpg (177.31 KiB) Viewed 406 times
Effectively a clear solution, with what might be super-fine aluminium oxide as a solid residue. I'll have to filter it and find out.
AEVA National President, retiring WA branch chair.